35y^2+44y=0

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Solution for 35y^2+44y=0 equation:



35y^2+44y=0
a = 35; b = 44; c = 0;
Δ = b2-4ac
Δ = 442-4·35·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-44}{2*35}=\frac{-88}{70} =-1+9/35 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+44}{2*35}=\frac{0}{70} =0 $

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